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If logy - dog x + los y), then show that |
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Answer» log(x+y/3)=1/2( log x + log y); log(x+y/3)=1/2 log xy log ( x+y/3)=log xy/2 ( x+y)/3=Vxy; . Vx/y + VY/X=3; squaring on both sides; (Vx/y)^2 + (Vy/x)^2=3^2; x/y + y/x =9;; |
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