If log2 = 0.301 and log3 = 0.4771, find the value of log^72^5

1.	If log2 = 0.301 and log3 = 0.4771, find the value of log^72^5
Answer» $\textbf{Formula used:}$ $\textbf{Product rule:}$ $\boxed{\bf\,log_a(MN)=log_aM+log_aN}$ $\textbf{Power rule:}$ $\boxed{\bf\,log_aM^n=n\;log_aM}$ $\textbf{Given:}$ $\log\,2=0.301\;\text{and}\;\log\,3=0.4771$ $\textbf{To <klux>FIND</klux>:}$ $\text{The value of $\log\,72^5$}$ $\text{Consider,}$ $\log\,72^5$ $\text{Using power rule of logarithm}$ $=5\,\log\,72$ $=5\,\log(8{\times}9)$ $\text{Using product rule of logarithm}$ $=5(\log\,8+\log\,9)$ $=5(\log\,2^3+\log\,3^2)$ $\text{Using power rule of logarithm}$ $=5(3\,\log\,2+2\,\log\,3)$ $=5(3(0.301)+2(0.4771))$ $=5(0.903+0.9542)$ $=5(1.8572)$ $=9.286$ $\therefore\textbf{The value of $\bf\log\,72^5$ is 9.286}$ Find more: Expand log 243 to the base 3 root 3 brainly.in/question/4637472# Expand log120/49 brainly.in/question/15415039 Evaluate log2 ^150 interms of X and y such that logo2 ^3=x and logo 2^5=y brainly.in/question/16242429

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