If log a−b2=12(log a+log b), show that: a2+b2=6ab

1.	If log a−b2=12(log a+log b), show that: a2+b2=6ab
Answer» If $l o g \frac{a - b}{2} = \frac{1}{2} (l o g a + l o g b)$ , show that: $a^{2} + b^{2} = 6 a b$

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