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If log 98+root x^2+12x+36=2 then find x |
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Answer» Answer Open in ANSWR app log
(x 2 −12x+36)=2 ⇒x 2 −12x+36=10 2 =100 ⇒x 2 −12x+36−100=0 ⇒x 2 −12x−64=0 ⇒x 2 −16x+4x−64=0 ⇒x(x−16)+4(x−16)=0 ⇒(x−16)(x+4)=0 ∴x=−4,16 Step-by-step explanation: this is the answer please mark as a BRAINLIST |
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