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If log 10 base 20+log10 base 30-1/2log 10 base 36log1020 + log1030 - \(\frac12\) log1036 |
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Answer» log1020 + log1030 - \(\frac12\) log1036 = log10(20 x 30) - log 10\(\sqrt{36}\) (\(\because\) log A + log B = log AB & n log A = log An) = log10600 - log106 = log10\((\frac{600}6)\)(\(\because\) log A - log B = log \(\frac AB\)) = log10100 = log10102 = 2 log10 10 (\(\because\) log an = n log a) = 2 (\(\because\) log1010 = 1) |
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