1.

If log 10 base 20+log10 base 30-1/2log 10 base 36log1020 + log1030 - \(\frac12\) log1036

Answer»

log1020 + log1030 - \(\frac12\) log1036

 = log10(20 x 30) - log 10\(\sqrt{36}\) (\(\because\) log A + log B = log AB & n log A = log An)

= log10600 - log106

= log10\((\frac{600}6)\)(\(\because\) log A - log B = log \(\frac AB\))

 = log10100

 = log10102

= 2 log10 10 (\(\because\) log an = n log a)

 = 2 (\(\because\) log1010 = 1)



Discussion

No Comment Found

Related InterviewSolutions