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If line `3x-ay-1=0` is parallel to the line `(a+2)x-y+3=0` then find the values of a. |
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Answer» The slope of the line `3x-ay-1=0` is `3//a`. The slope of the line `(a+2)x-y+3=0` is `a+2`. Since the lines are parallel, we have `a+2(3)/(a)` or `a^2+2a-3=0` or `(a-1)(a+3)=0` or `a=1or a=-3`. |
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