If limiting molar conductivity of Ca2+ and Cl– are 119.0 and 76.3 S cm2 mol-1, then the value of limiting molar conductivity of CaCl2 will be (a) 195.3 S cm2 mol-1 (b) 271.6 S cm2 mol-1 (c) 43.3 S cm2 mol-1 (d) 314.3 S cm2 mol-1.

If limiting molar conductivity of Ca2+ and Cl– are 119.0 and 76.3 S

1.	If limiting molar conductivity of Ca2+ and Cl– are 119.0 and 76.3 S cm2 mol-1, then the value of limiting molar conductivity of CaCl2 will be (a) 195.3 S cm2 mol-1 (b) 271.6 S cm2 mol-1 (c) 43.3 S cm2 mol-1 (d) 314.3 S cm2 mol-1.
Answer» re option (b) is correct choice.Given : If limiting MOLAR CONDUCTIVITY of Ca²⁺ and Cl¯ are 119.0 and 76.3 S cm² MOL¯¹. To find : The value of limiting molar conductivity of CaCl₂. solution : from Kohlrausch's law, ⇒ = 119 + 2 × 76.3 = 119 + 152.6 = 271.6 cm²mol¯¹ The limiting molar conductivity of CaCl₂ is 271.6 cm²mol¯¹Therefore option (b) is correct choice.also read SIMILAR questions : The molar conductivity of 0.025 mol L−1 methanoic acid is 46.1 S cm2 mol−1 . brainly.in/question/5247791From the following molar conductivities at infinite dilution,Am for Al2(SO4)3 = 858 S cm2 mol-'An for NH,OH = 238.3... brainly.in/question/10255022