1.

If lamda_(1) and lamda_(2)denote the wavelengths of de-Broglie waves for electrons in the first and second Bohr orbits in hydrogen atom, then (lamda_(1))/(lamda_(2)) is equal to :

Answer»

`(2)/(1)`
`(1)/(2)`
`(1)/(4)`
`(4)/(1)`

SOLUTION :In CASE of FIRST Bohar ORBIT n=1.
`E_(1)=-13*6eV`
For Bohar.s second orbit n=2
`E_(2)-(13*6)/(2^(2))=(-13*6)/(4)eV`
As `E=(hc)/(lambda)rArr Eprop (1)/(lambda)`
`:. (lambda_(1))/(lambda_(2))= sqrt((E_(2))/(E_(1)))= sqrt((1)/(4))=(1)/(2)`


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