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If lamda_(1) and lamda_(2)denote the wavelengths of de-Broglie waves for electrons in the first and second Bohr orbits in hydrogen atom, then (lamda_(1))/(lamda_(2)) is equal to : |
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Answer» `(2)/(1)` `E_(1)=-13*6eV` For Bohar.s second orbit n=2 `E_(2)-(13*6)/(2^(2))=(-13*6)/(4)eV` As `E=(hc)/(lambda)rArr Eprop (1)/(lambda)` `:. (lambda_(1))/(lambda_(2))= sqrt((E_(2))/(E_(1)))= sqrt((1)/(4))=(1)/(2)` |
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