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If kinetic energy of a body is increased by 300% then percentage change in momentum will be(1) 100%(2) 150%(3) 265%(4) 73.2% |
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Answer» 173.2%Explanation:SINCE KE= mv²/2KE2/KE1= V2²/V1²= 3=> V2/V1= √3momentum= mv=> mv2/mv1= √3×mincrement = √3% INCREMENT in MOMENTUM= √3×100 = 173.2% |
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