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If kcl crystallizes in fcc lattice then number of unit cells in its 0.2mol is

Answer»

Explanation:no. of ATOMS in KCl =mole × NA( avogadro's no)                                 = 0.2 × 6.022 × 10^ 23                                 =1.20 × 10^23now FCC LATTICE contains 4 atoms per UNIT cellso for 1.20 × 10^ 23 it will be = 1.20 × 10^23/4                                                = 3.01 × 10^22I HOPE THIS IS HELPFULTHANKS



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