If K(x) = 3x – 9 then L(x) = 7x – 10 then LOK is …(1) 21x + 73(2 – InterviewSolution

1.

If K(x) = 3x – 9 then L(x) = 7x – 10 then LOK is …(1) 21x + 73(2) – 21x + 73(3) 21x – 73(4) 22x – 73

Answer»

(3) 21x – 73

K(x) = 3x – 9; L(x) = 7x – 10

LOK = L[K(x)]

= L(3x – 9)

= 7(3x – 9) – 10

= 21x – 63 – 10

= 21x – 73

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