1.

If is an acute angle and sin cose, then the value of2 tan 0 cose-2 is​

Answer»

ong>Step-by-step explanation:

sinθ=cosθ

cosθ

ssin =cosθ

ccos

tanθ=1=tan45 o

θ=45 o

Therefore, 2tan

θ

+SIN

2

θ−1=2tan

45o+sin2

45o−1=2×(1)

2+( 2

1) 2−1=2+

2

1−1=2

3



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