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If is an acute angle and sin cose, then the value of2 tan 0 cose-2 is |
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Answer» ong>Step-by-step explanation: sinθ=cosθ cosθ ssin =cosθ ccos tanθ=1=tan45 o θ=45 o Therefore, 2tan θ +SIN θ−1=2tan 45o+sin2 45o−1=2×(1) 2+( 2 1) 2−1=2+ 2 1−1=2 |
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