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If in two triangles ABC and PQR, AB/QR = BC/PR = CA/PQ, then (A)Δ PQR ~ Δ CAB (B) Δ PQR ~Δ ABC(C)Δ CBA ~ Δ PQR (D) Δ BCA ~ Δ PQR |
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Answer» Correct answer is (A)Δ PQR ~ Δ CAB |
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