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If in triangle ABC, sides opposite to angles A,B,C are a,b and c respectively, then the value of 1+cos(A−B)cosC1+cos(A−C)cosB= |
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Answer» If in triangle ABC, sides opposite to angles A,B,C are a,b and c respectively, then the value of 1+cos(A−B)cosC1+cos(A−C)cosB= |
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