Related InterviewSolutions

• `"cosec"theta+cottheta=sqrt(3)`
• `3(sintheta-costheta)^(4)+6(sintheta+costheta)^(2)+4(sin^(6)theta+cos^(6)theta)=?`
• `sqrt(3)costheta+sintheta=2`
• Prove that : `(sintheta)/(1+costheta)+(1+costheta)/(sintheta)=2"cosec"theta`
• `sintheta=-1/2` and `costheta=-sqrt(3)/2`
• The number of solutions of the equation `sintheta+costheta=2` are:A. 1B. 2C. 0D. infinite
• Find the general values of `theta` from the following equations: i) `sin3theta=cos3theta` ii) `2cos^(2)theta=1-2sinthetacostheta` iii) `"cosec"^(2)theta+2"cosec"theta-3=0`
• If `sintheta-3sin2theta+sin3theta=costheta-3cos2theta+cos3theta`, then one of the general value is:A. `(npi)/(2)+pi/8`B. `npi+pi/8`C. `npi-pi/8`D. `(npi)/(2)-pi/8`
• Find the general values of `theta` from the following equations: i) `sintheta=-sqrt(3)/(2)` ii) `sectheta=-sqrt(2)` iii) `cottheta=-1/sqrt(3)`, iv) `"cosec"theta=-2`
• If `(2+sqrt(3))costheta=1-sintheta`, then one general value is:A. `2npi+pi/2`B. `npi+pi/2`C. `npi+pi/3`D. None of these