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If in an AP. , S5-35 and S4th22 find the 5 term. |
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Answer» S5=35 n=5 Formula Si=n/2(2a+(n-1)d) 35=5/2(2a+4d) 70=5(2a+4d) 5(14)=5(2a+4d) 14=2a+4d…………1 S4=22 n=4 22=4/2(2a+3d) 11=2a+3d……..2 1–2 d=3 Substitute d value in 2 11=2a+3(3) 11=2a+9 2a=11–9 2a=2 a=1 Formula Si=n/2(a+ai) S5=n/2(a+a5) 35=5/2(1+a5) 14=1+a5 a5=13 5th term 13 |
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