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If in an a.p.an=mam=na(n+m)=? |
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Answer» ong>Answer: Step-by-step explanation: am = a + (m – 1)d an = a + (n - 1)d It is GIVEN that m(am) = n(an) m{a + (m – 1)d} =n{a+ (n – 1)d} ma + m(m – 1)d = na + n(n – 1)d ma — na = = d(n² – n – m² +m) a(m – n) = d(n – m)(m +n – 1) a = -d(m +n - 1) a+(m+n-1)d=0 Now (m + n)TH term is a(m+n) = a+(m+n – 1)d = 0 |
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