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If in a triode valve amplification factor is 20 and plate resistance is `10 kOmega` , then its mutual conductance isA. 2 milli mhoB. 20 milli mhoC. (1/2) milli mhoD. 200 milli mho |
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Answer» Correct Answer - A Amplificantion factor `mu= 20` Plante resistance `R_(p)= 10 K Omega = 10 xx 10 ^(-3) Omega` `therefore` Mutual conductance `g_(m)= (mu)/(R_(p))` ` = (20)/( 10 xx 10^(3))` `= 2 xx 10 ^(3) " mho or 2 milli mho "` |
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