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if in a nuclear fusion reaction, mass defect to 0.3% , then energy released in fusion of 1 kg mass

Answer»

`27xx10^10` J
`27xx10^11` J
`27xx10^12` J
`27xx10^13` J

Solution :Here, `Deltam`=0.3% of 1 KG
`=0.3/100 kg =3XX10^(-3)` kg
`THEREFORE E=(Deltam) c^2=3xx10^(-3)xx(3xx10^8)^2=27xx10^13` J


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