1.

If HCF of number 408 and 103 is expressed in form of 1032x-408×5 then find the value of x​

Answer»

Answer:

408=2×2×2×3×17

1032=2×2×2×3×43

Hence, HCF=2×2×2×3=24

Now, 1032x−408×5=24⇒1032x=2064⇒x=2

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