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IF have energy of a 100 mu F capacitor charge to 6kV could all be used to lift a 50 kg mass, then the greatest vertical height through which mass could be raised in…… m |
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Answer» 3.6 `therefore H=(CV^2)/(2MG)=(100 times 10^-6 times (6 times 10^3)^2)/(2 times 50 times 10)` `=3.6m` |
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