1.

IF have energy of a 100 mu F capacitor charge to 6kV could all be used to lift a 50 kg mass, then the greatest vertical height through which mass could be raised in…… m

Answer»

3.6
0.6
1.2
12

Solution :`1/2 CV^2= mgh`
`therefore H=(CV^2)/(2MG)=(100 times 10^-6 times (6 times 10^3)^2)/(2 times 50 times 10)`
`=3.6m`


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