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If `hatn=ahati+bhatj` is perpendicualr to the vector `(hati+hatj)`, then the value of a and b may be:A. 1,0B. `-2,0`C. 3,0D. `(1)/sqrt(2),-(1)sqrt(2)` |
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Answer» Correct Answer - D `hatn=ahati+bhatjrArrsqrt(a^(2)+b^(2))=1` or `a^(2)+b^(2)=1` `(ahati+bhatj).(hati+hatj)=0` a+b=0 `a^(2)+b^(2)=1` `a=(1)/sqrt(2),b=(-1)/sqrt(2)` |
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