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If `|hata-hatb|=sqrt(2)` then calculate the value of `|hat a+sqrt(3)hatb|`. |
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Answer» Let `theta` be the angle between `hata & hatb` then `|hata-hatb|=sqrt(1^(2)+1^(2)-2(1)(1)costheta)=sqrt(2)rArr cos theta=0` `|hata+sqrt(3)hatb|=sqrt(1+3+2sqrt(3)cos theta)=sqrt(1+3)=2` |
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