If h is the height or depth (sagitta) of a spherical surfacce and I is the mean distance between the legs of sphermoeter, then radius of curvature R of the surface is

If h is the height or depth (sagitta) of a spherical surfacce and I is

1.	If h is the height or depth (sagitta) of a spherical surfacce and I is the mean distance between the legs of sphermoeter, then radius of curvature R of the surface is
Answer» `R =(I^2)/(H) + (h)/(2)` `R = (I^2)/(6H) + (h)/(2)` `R =(I^2)/(6h) - (h)/(2)` `R = (h^2)/(6I) + (I)/(2)` Solution :The correct relation for R is `R = (I^2)/(6h) + (h)/(2)`