1.

If 'g' on the surface of the earth is 9.8ms^(-2), find its value at a depth of 3200 km (radius of the earth = 6400 km)

Answer»

SOLUTION :with d = 3200 km
`g_(d) = g[1-(d)/(R)]RARR g_(d) = 4.9 ms^(-2)`


Discussion

No Comment Found