If \(\frac{x}4+\frac{y}3= -\frac{15}{12}\) and \(\frac{x}2+y = 1\),

1.	If \(\frac{x}4+\frac{y}3= -\frac{15}{12}\) and \(\frac{x}2+y = 1\), y then find the value of (x + y).
Answer» The given pair of equations is \(\frac{x}4+\frac{y}3= -\frac{15}{12}\)........(i) \(\frac{x}2+y = 1\)......(ii) Multiplying (i) by 12 and (ii) by 4, we have 3x + 4y = 5 ……….(iii) 2x + 4y = 4 ………(iv) Now, subtracting (iv) from (iii), we get x = 1 Putting x = 1 in (iv), we have 2 + 4y =4 ⇒ 4y = 2 ⇒ y = 1/2 ∴ x + y = 1 + 1/2 = 3/2 Hence, the value of x + y is 3/2 .

If \(\frac{x}4+\frac{y}3= -\frac{15}{12}\) and \(\frac{x}2+y = 1\), y then find the value of (x + y).

Answer»

The given pair of equations is

\(\frac{x}4+\frac{y}3= -\frac{15}{12}\)........(i)

\(\frac{x}2+y = 1\)......(ii)

Multiplying (i) by 12 and (ii) by 4, we have

3x + 4y = 5 ……….(iii)

2x + 4y = 4 ………(iv)

Now, subtracting (iv) from (iii), we get

x = 1

Putting x = 1 in (iv), we have

2 + 4y =4

⇒ 4y = 2

⇒ y = 1/2

∴ x + y = 1 + 1/2 = 3/2

Hence, the value of x + y is 3/2 .