If \frac{\sin (\theta+A)}{\sin (\theta+B)}=\sqrt{\frac{\sin 2 A}{\sin – InterviewSolution

1.	If \frac{\sin (\theta+A)}{\sin (\theta+B)}=\sqrt{\frac{\sin 2 A}{\sin 2 B}} then tan^2 theta=?a)tan A b)tanB c)tanA+tanB d)tanAtanB
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