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If f(x+y+1)=(√f(x)+√f(y))2 ∀ x,y∈R and f(0)=1, then the value of f(12)+f(1)+f(2) is |
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Answer» If f(x+y+1)=(√f(x)+√f(y))2 ∀ x,y∈R and f(0)=1, then the value of f(12)+f(1)+f(2) is |
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