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If f(x)=x3+bx2+ax satisfies the condition of Rolle's theorem on [1,3] with c=2+1√3. Then (a+b)= |
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Answer» If f(x)=x3+bx2+ax satisfies the condition of Rolle's theorem on [1,3] with c=2+1√3. Then (a+b)= |
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