If f(x)=⎧⎪⎨⎪⎩x3−2x2−15x+36(x−3)2,x≠3p,x=3 is continu – InterviewSolution

1.	If f(x)=⎧⎪⎨⎪⎩x3−2x2−15x+36(x−3)2,x≠3p,x=3 is continuous at x=3, then the value of p is
Answer» If $f (x) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} \frac{x^{3} - 2 x^{2} - 15 x + 36}{(x - 3)^{2}}, & x \neq 3 p, & x = 3 \end{matrix}$ is continuous at $x = 3$ , then the value of $p$ is

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