1.

If f(x)={x2+B+1,x<03Ax+2,x≥0 is differentiable at x=0, then the value of A+B is (where A and B are real constants)

Answer» If f(x)={x2+B+1,x<03Ax+2,x0 is differentiable at x=0, then the value of A+B is (where A and B are real constants)


Discussion

No Comment Found