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If f(x)={x2+B+1,x<03Ax+2,x≥0 is differentiable at x=0, then the value of A+B is (where A and B are real constants) |
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Answer» If f(x)={x2+B+1,x<03Ax+2,x≥0 is differentiable at x=0, then the value of A+B is |
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