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If f(x)=sin−1(cosx)cos−1(sinx) ∀x∈[0,2π], then the number of point(s) of non differentiability is |
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Answer» If f(x)=sin−1(cosx)cos−1(sinx) ∀x∈[0,2π], then the number of point(s) of non differentiability is |
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