Saved Bookmarks
| 1. |
If f(x) is twice differentiable function such that f(a)=0, f(b)=2, f(c)=−1, f(d)=2, f(e)=0, where a<b<c<d<e, then the minimum number of zeroes of g(x)=(f′(x))2+f′′(x)f(x) in the interval [a,e] is |
|
Answer» If f(x) is twice differentiable function such that f(a)=0, f(b)=2, f(c)=−1, f(d)=2, f(e)=0, where a<b<c<d<e, then the minimum number of zeroes of g(x)=(f′(x))2+f′′(x)f(x) in the interval [a,e] is |
|