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If f (x) = ex and g(x) = loge x, then which of the following is true ?(a) f {g (x)} ≠ g{f (x)} (b) f {g (x)} = g{f (x)} (c) f {g (x)} + g{f (x)} = 0(d) f {g (x)} – g{f (x)} = 1 |
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Answer» Answer : (b) f {g (x)} = g{f (x)} f (x) = ex and g(x) = loge x ∴ f {g (x)} = f (loge x) = eloge x = x = g{f (x)} = g (ex ) = logeex = x ∴ f {g(x)} = g{f (x)}. |
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