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If f(x)=⎧⎪⎨⎪⎩ax2−b,|x|<1−1|x|,|x|≥1 is differentiable at x=1, then the value of a+b is

Answer» If f(x)=ax2b,|x|<11|x|,|x|1 is differentiable at x=1, then the value of a+b is


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