1.

If f (x) = a cos x + bx sin x + 4x - 3x2 - 2x3 and f (3) = 48, then f (- 3) =

Answer»

f(x)=acosx+bxsinx+4x-3x^2-2x^3

=>f(3)=acos3+3bsin3+4*3-3*3^2-2*3^3

=>48=acos3+3bsin3-69

=>acos3+3bsin3=117

Now

f(-3)=acos(-3)+b(-3)sin(-3)+4*(-3)-3(-3)^2-2(-3)^3

f(-3)=acos3+3bsin3-12-27+54

=117-39+54=132



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