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If f'(x) = 9x2 – 6x and f(0) = -3; find f(x) |
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Answer» f'(x) = ∫(9x2 – 6x) dx f(x) = 9x3/3 - 6x2/2 + c f(x) = 3x3 – 3x2 + c But f(0) = -3 3(0)3 – 3(0)2 + c = -3 c = -3 Thus, f(x) = 3x3 – 3x2 – 3 f(x) = 3(x3 – x2 – 1) |
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