If f(x)=6∫x2+2x(x2+x+1)2dx,(x≥0) and f(0)=1, then the value of f(1) is

If f(x)=6∫x2+2x(x2+x+1)2dx,(x≥0) and f(0)=1, then the value of f(1

1.	If f(x)=6∫x2+2x(x2+x+1)2dx,(x≥0) and f(0)=1, then the value of f(1) is
Answer» If $f (x) = 6 \int \frac{x^{2} + 2 x}{(x^{2} + x + 1)^{2}} d x, (x \geq 0)$ and $f (0) = 1$ , then the value of $f (1)$ is