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If f'(x) = 4x – 5 and f(2) = 1; find f(x) |
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Answer» ∫f'(x) dx = ∫(4x – 5) dx f(x) = 4x2/2 - 5x + c f(x) = 2x2 – 5x + c But f(2) = 1 2(2)2 – 5(2) + c = 1 8 – 10 + c = 1 c = 3 Thus, f(x) = 2x2 – 5x + 3 |
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