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If f(x)=∫2x5+5x4(4+2x+3x5)2dx,(x≥0) and f(0)=0, then the value of 72⋅f(1) is

Answer» If f(x)=2x5+5x4(4+2x+3x5)2dx,(x0) and f(0)=0, then the value of 72f(1) is


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