1.

If f(x)=⎧⎪⎪⎪⎨⎪⎪⎪⎩(1−cospx)(2x−1)(√1+x2−1)sinx ; x≠012 ; x=0 is continuous, then the value of ep2+1p2 is

Answer»

If f(x)=



(1cospx)(2x1)(1+x21)sinx ; x012 ; x=0


is continuous, then the value of ep2+1p2 is



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