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If `f:RtoR` is given by `f(x)=3x-5` then `f^-1(x)`A. is given by `(1)/(3x-5)`B. is given by `(x+5)/(3)`C. does not exist because f is not one-oneD. does not exist because is not onto |
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Answer» Correct Answer - B Clearly, `f: R to R` is a one-one onto function, So, it is invertible. Let f(x)=y. Then, `3x-5=y Rightarrow x=(y+5)/(3) Rightarrow f^(-1)(y)=(y+5)/(3)` Hence, `f^(-1)(x)=(x+5)/(3)` |
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