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If f : R → R and g : R → R are defined by f (x) = x – 3 and g (x) = x2 + 1, then find the values of x for which g {f (x)} = 10. |
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Answer» g{f (x)} = g (x – 3) = (x – 3)2 + 1 = x2 – 6x + 9 + 1 = x2 – 6x + 10. Given, g{f (x)} = 10 ⇒ x2 – 6x + 10 = 10 ⇒ x2 – 6x = 0 ⇒ x (x – 6) = 0 ⇒ x = 0, 6. |
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