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If f:[−2,2]→R is differentiable such that f(0)=2, f′(0)=−1 and h(x)=f(f(x)2+f(x)−6), then the value of h′(0) is |
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Answer» If f:[−2,2]→R is differentiable such that f(0)=2, f′(0)=−1 and h(x)=f(f(x)2+f(x)−6), then the value of h′(0) is |
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