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If `F_(1)` and `F_(2)` are the feet of the perpendiculars from the foci `S_(1)` and `S_(2)` of the ellipse `(x^(2))/(5)+(y^(2))/(3)=1` on the tangent at any point P on the ellipse, then `(S_(1)F_(1))(S_(2)F_(2))` is equal toA. 2B. 3C. 4D. 5 |
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Answer» Correct Answer - B We know that the product of the perpendiculars from the two foci of an ellipse upon any tangent is equal to the square of the semi-minor axis. Thus `(S_(1)F_(1))(S_(2)F_(2))=3` |
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