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If `emf` of battery is `100V`, then what was the resistance of Rheostat adjusted at reading (`i=2A`, `V=20V`) A. `10 Omega`B. `20 Omega`C. `30 Omega`D. `40 Omega` |
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Answer» Correct Answer - D from the curve slope `=(1)/(v)=(1)/(R )=(1)/(10)` , `R=10Omega` for second reading `i=(Emf)/(R+R_(rh)implies 2=(100)/(10+R_(rh))impliesR_(rh)=40Omega` |
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