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If `emf` of battery is `100V`, then what was the resistance of Rheostat adjusted at reading (`i=2A`, `V=20V`) A. `10Omega`B. `20Omega`C. `30Omega`D. `40Omega` |
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Answer» From the curve slope `= (I)/(v) = (1)/(R) = (1)/(10) R = 10Omega` for second reading `I = (Emf)/(R+R_(rh)) 2 = (100)/(10 + R_(rh)) rArr R_(rh) = 40Omega` . |
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