If element with principal quantum no n>4 were not allowed in nature ,

1.	If element with principal quantum no n>4 were not allowed in nature , then the no of possible elements would be 1)60. 2)32. 3)4. 4)64
Answer» Answer:60 Explanation: For calculating GROUND state of an element we USE the formula 2n^2 THEREFORE.. For n = 1 , 2n^2=2. Same for n= 2 , 8. n = 3 , 18. n = 4 , 32. Therefore 2+8+18+32=60. As n>4.

If element with principal quantum no n>4 were not allowed in nature , then the no of possible elements would be 1)60. 2)32. 3)4. 4)64

Answer»

Answer:60

Explanation:

For calculating GROUND state of an element we USE the formula 2n^2

THEREFORE..

For n = 1 , 2n^2=2.

Same for n= 2 , 8.

n = 3 , 18.

n = 4 , 32.

Therefore 2+8+18+32=60.

As n>4.

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If element with principal quantum no n>4 were not allowed in nature , then the no of possible elements would be 1)60. 2)32. 3)4. 4)64

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