If ef(x)=10+x10−x,x∈(−10,10) and f(x)=kf(200x100+x2) then k=

1.	If ef(x)=10+x10−x,x∈(−10,10) and f(x)=kf(200x100+x2) then k=
Answer» If $e^{f (x)} = \frac{10 + x}{10 - x}, x \in (- 10, 10)$ and $f (x) = k f (\frac{200 x}{100 + x^{2}})$ then $k =$

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