If each of the dimensions of a rectangle is incresed by 100%, then the

1.	If each of the dimensions of a rectangle is incresed by 100%, then the area is increased by
Answer» Answer: $Let \: the \: original \: l\:<klux>LENGTH</klux> \: of \: rectangle$ be.L,breadth be B and area be A A=L×B=LB New length,L1=L+100%L =L+100L100 =L+L=2L New breadth,B1=B+100%B =B+100B100 =B+B=BL New Area,A1=L1×B1=2L×2B=4LB Change in area=A1−A =4LB−LB=3LB Increase in area in percent =Change in area Original area×100 =A1−AA×100 =3LBLB×100 =300% THEREFORE area INCREASES by =300% Step-by-step explanation: *hope* it *helped* *you* *friend* if it *helps* *you* *mark* it as *brainliest* *HAPPY* *learning*

If each of the dimensions of a rectangle is incresed by 100%, then the area is increased by

Answer»

Answer:

$Let \: the \: original \: l\:<klux>LENGTH</klux> \: of \: rectangle$

be.L,breadth be B and area be A

A=L×B=LB

New length,L1=L+100%L

=L+100L100

=L+L=2L

New breadth,B1=B+100%B

=B+100B100

=B+B=BL

New Area,A1=L1×B1=2L×2B=4LB

Change in area=A1−A

=4LB−LB=3LB

Increase in area in percent

=Change in area Original area×100

=A1−AA×100

=3LBLB×100

=300%

THEREFORE area INCREASES by =300%

Step-by-step explanation:

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If each of the dimensions of a rectangle is incresed by 100%, then the area is increased by​

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If each of the dimensions of a rectangle is incresed by 100%, then the area is increased by